Please help 2) Solve for b^2 in the following equation
a^2 + b^2 = c^2

3) Solve for h in the following equation. A = bh

4) Solve for r in the following equation. l = Prt

5) Solve for b in the following equation. Try this with a fraction! A = 1/2 bh

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.

b and c

step-by-step explanation:

27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629