Suppose U1 and U2 are two open sets in R^n with U1∩U2 non-empty and path connected. Suppose there exists an f1 : U1 → R and f2 : U2 → R, both twice continuously differentiable such that d f1 = d f2 on U1 ∩ U2. Then there exists a twice differentiable function F : U1 ∪U2 → R such that dF = d f1 on U1 and dF = d f2 on U2

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

answer: you will have more water.

feed your rabbit lettuce.