Here is a sample data set that appears to be nearly normal (as suggested by the histogram). 69.8 86.4 66 80.7 66.5 62.4 79.4
72 74.4 62.5 64.6 68.4 66 81.8
73.5 80.7 71.6 55.5 65.6 76.5 63.5
74.7 69.6 76.2 | 67.1 73 65.3 61
88.4 80.771.4 84 75.1 53.668
73.3 72.9 62.7 76.9 61.4 66.3 72.9
54.3 64.9 72.9 65.6 74 71.8 64.3
67.1 | 66.7 62.4 72 70.6 63.5 81.2
60.6 | 74.7 57.6 82.476.5 74.9 59.7
75.1 68.6 71.6 57.6 71.2 71.2 70.2
20
15
Frequency
10
50 55 60 65 70 75 80 85 90
length (cm)

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

step-by-step explanation:

goog be able to you with that maybe

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x