In how many ways can you arrange MATHEMATICS if duplication of the arrangement are not allowed?​

4989600 ways

Step-by-step explanation:

From the question,

The word MATHEMATICS can be arranged in n!/(r₁!r₂!r₃!)

⇒ n!/(r₁!r₂!r₃!) ways

Where n = total number of letters, r₁ = number of times M appears r₂ = number of times A appears, r₃ = number of times T appears.

Given: n = 11, r₁ = 2, r₂ = 2, r₃ = 2

Substitute these value into the expression above

11!/(2!2!2!) = (39916800/8) ways

4989600 ways

Hence the number of ways MATHEMATICS can be arranged without duplicate is 4989600 ways

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it