A ball, dropped vertically, falls d metres in t seconds. d is directly proportional to the square of t.
The ball drops 45 metres in the first 3 seconds.
How far does the ball drop in the next 7 seconds?

455m

Step-by-step explanation:

We know that acceleration is acceleration due to gravity, which is 10m/s, and initial speed u=0m/s

Use the motion equation to find distance when t=10:

d=ut+(1/2)at²

d=0t+(1/2)(10)(10²)

d=500m

The distance travelled in the seven seconds following the first three = 500-45=455m

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632