HELP Puzzle Four
Answer the following problems and then find the sum of all your
answers to unlock puzzle four.
1550
1
3
4
2)
3)
m21
mz 4
mus
m27
6
7
5)
mzCDE
5x + 15
B-42
6)
MZABC
110
3
А
O
7)
MZMNO
1151
M
Code:
the Midwest 2009

1) m<1 = 25

2) m<4 = 155

3) m< 5 = 25

4) m<7 = 25

5) 110

6) 30.5

7) 74

Step-by-step explanation:

1)

x + 155 = 180

x = 25

2)

<4 = 155 because of vertical angle thm

3)

<5 = 25 (congruent to <1) b/c of corresponding angles thm

4)

<7 = <5 (25) because of vertical angles thm

5)

5x + 15 = 8x - 42

-3x = -57

x = 19

5(x) + 15

5(19) + 15 = 110

6)

180 - 110 = 70

3x + x + 4 + 70 = 180

4x + 74 = 180

4x = 106

x = 26.5

x+ 4 = 30.5

7)

180 - 115 = 65

x + 4 + 2x + 65 = 180

3x + 69 = 180

3x = 111

x = 37

2x = 74

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!