A rectangle with a length of x + 5 has a perimeter of 4x + 14. 1. Write the expression for the width of the rectangle in terms of x.
2. Suppose the perimeter of the rectangle is 42 inches. What are the length and
width of the rectangle?
3. Write the expression for the area of the rectangle in terms of x.
4. What is the area of the rectangle when x = 7?
Show how t get the answer

1. Width = x + 2

2. Length = 12; width = 9

3. x² + 7x + 10

4. 108

Step-by-step explanation:

perimeter = 4x + 14

length = x + 5

1. Perimeter of a rectangle = 2(length + width)

4x + 14 = 2{(x + 5) + width}

4x + 14 = 2x + 10 + 2width

4x + 14 - 2x - 10 = 2width

2x + 4 = 2width

Width = (2x + 4)/2

Width = x + 2

2. Perimeter of a rectangle = 2(length + width)

42 = 2{(x + 5) + (x + 2)}

42 = 2x + 10 + 2x + 4

42 = 4x + 14

42 - 14 = 4x

28 = 4x

x = 28/4

x = 7

length = x + 5

= 7 + 5

= 12

Width = x + 2

= 7 + 2

= 9

3. Area of the rectangle = length × width

= (x + 5)(x + 2)

= x² + 2x + 5x + 10

= x² + 7x + 10

4. Area of the rectangle = x² + 7x + 10

When x = 7

x² + 7x + 10

= 7² + 7(7) + 10

= 49 + 49 + 10

= 108

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet