Graph the point on the coordinate plane.

go to the seventh unit (to the right, from the middle of the graph) and downwards two times! then graph the point there.

Step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation: