a triangular land having area 36m²and perimeter 84 m has length of the edge 26m. Calculate the measure of remaining two sides​

Complete question :

a triangular land having area 36m²and perimeter 84 m has length of the edge 26m. Calculate the measure of remaining two sides​

28cm, 30 cm

Step-by-step explanation:

Area = 336 m³ ; lebgth of edge = 26

Perineter, p = 84

Perimeter of triangle :

a + b + c

Length of other two sides = 84 - 26 = 58

If length of one of the sides = x

Lenvyb if the other = 58 - x

From Hero's formular :

Sqrt(s(s-a)(s-b)(s-c).

s = perimeter /2 = 84/2 = 42

Sqrt(42(42 - 26)(42 - x)(42 - (58-x))

sqrt(42(16)(42-x)(42-58+x) = 336

sqrt(42(16)(42-x)(-16+x) = 336

672(42-x)(x - 16) = 112896

(42 - x)(x - 16) = 168

42x - 672 - x² + 16x = 168

-x² + 58x - 840 = 0

Using the quadratic equation solver, the roots are :

28, 30

Hence.the other tow sides are 28 cm and 30 cm

idk

step-by-step explanation:

arc length = 6.63311 ft.

step-by-step explanation:

the formula the arc measure is:

arc length s=2πr(c)/360

where:

c   is the central angle of the arc in degrees

r   is the radius of the arc

π   is pi, approximately 3.142

using the above formula we get

s =

thus we find that arc length of an arc for a circle of radius 20 feet and central angle 19 degrees is

6.63311 feet