PLZZ HELP! THIS IS REALLY IMPORTANT Mary worked from Monday to Saturday last week and bought lunch in the company’s restaurant every day. Her lunches cost a different amount every day. Each lunch cost a multiple of 20¢.The most expensive lunch of the week cost $7.60 and the cheapest one cost $4.40.Friday’s lunch cost exactly 1½ times as much as Wednesday’s lunch. Tuesday’s lunch cost $1.20 more than Thursday’s lunch. (a) What is the minimum total that Mary’s six lunches last week could have cost? what is the maximum cost for the week?

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

900 degrees

step-by-step explanation: