Which equation is parallel to the graph of y = 2x-5 and goes through the point (3,9)? Why is it right?

y = 2x + 3

Step-by-step explanation:

the slope is 2 so the line parallel will have a slope of 2

y-9 = 2(x-3)

y-9= 2x - 6

y = 2x +3

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

step-by-step explanation:

yes it represnts a functio, their are not 2 of the same numbers on the both sides