The daily water consumption for an Ohio community is normally distributed with a mean consumption of 519,645 gallons and a standard deviation of 71,564 gallons. The community water system will experience a noticeable drop in water pressure when the daily water consumption exceeds 782,238 gallons. What is the probability of experiencing such a drop in water pressure

0.0001

Step-by-step explanation:

The computation of the probability of experiencing such a drop in water pressure is shown below:

Given that

mean = 519,645 gallons

Standard deviation = 71,564 gallons

Now the probability is

= 1 - p (x - mean ÷ standard deviation <  782,238 - 519,645 ÷ 71,564)

= 1 - p(z<3.67)

= 1 - 0.9999

= 0.0001

10

step-by-step explanation:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6