Please help! Will give brainliest! 1.Write the equation in point-slope form with the given slope of -2 and passes through the point (4,-5)

2. Write the equation in slope-intercept form of the line parallel to y=4x-2 and passes through (4,6)

3. Write the equation in slope-intercept form with the given slope of 3 and passes through (-1,1)

4. Write the equation in slope-intercept form of the line perpendicular to 2x-7y=1 and passes through (0,-4)

The equation in point-slope form:  y - y₁ = m(x - x₁)

slope:  m = -2

point:   (4, -5)   ⇒   x₁ = 4, y₁ = -5

Therefore, the equation of the line in point-slope form:

The equation in slope-intercept form:   y = mx + b

Parallel lines has the same slope, so:

y = 4x + 2     ⇒    a = 4

If a line passes through the point (x₁, y₁) then the equation y₁ = mx₁ + b is true.

(4, 6)  ⇒   x₁ = 4, y₁ = 6  

So:   6 = 4·4 + b  ⇒   b = -10

Therefore the equation:  

a = 3

(-1, 1)  ⇒   x₁ = -1, y₁ = 1  

So:   1 = 3·(-1) + b  ⇒   b = 4

The equation:  

The product of slopes of perpendicular lines is -1.

2x - 7y = 1    ⇒  7y = -2x + 1   ⇒  y = -²/₇x + ¹/₇

-²/₇×m = -1    ⇒   m = ⁷/₂

(0, -4)  ⇒   x₁ = 0, y₁ = -4  

-4 = ⁷/₂·0 + b   ⇒   b = -4

The equation:

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.