Find the value of k that makes the function continuous

13/3

OR

4.33333

Step-by-step explanation:

For this function to be continuous, the second function must have the value of the limit as x approaches 3 of the first function.

To find we have to factor the top of the fraction

2x^2 - 3 -15

2x^2 - 18

2* (x^2 - 9)

2 * (x + 3) (x - 3)

this is perfect because this cancels out the x - 3 on the bottom

so the function become f(x) = 2 * (x + 3)

When 3 is plugged in it becomes 2 * (3 + 3) = 2 * 6 = 12

Now if you plug in 3 to the second function and make it equal to 12, you can find the value of k.

k*(3) - 1 = 12

k*3 = 13

k = 13/3

k = 4.33

109 is the nearest whole number/final answer! : )

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2