Rate of change , you are given the dollar value of a product in 2004 and the rate at which the value of the product is expected to change during the next 5 years. write a linear equation that gives the dollar value (v) of the product in terms of the year
(let t=0 represent 2000.)

2004 value= $156 with $4.50 increase per year

The linear equation is v = 4.5t +138

The product had value of $138 in 2000.

Step-by-step explanation:

In 2004, dollar value(v) = $156 and rate of change (m) = $4.50

The linear equation is in the form of y = mx + b, where "m" is slope or rate of change, b is the y-intercept.

We can rewrite the equation as v = m(t) + b.

Now let's find the value of b, when t = 4, m = 4.5, v = 156

156 = 4.5(4) + b

b = 156 - 4.5(4)

b = 156 - 18

b = 138

So, the linear equation is v = 4.5t +138

When t=0, the dollar value (v) = 4.5(0) + 138

v = $138

So, the product had value of $138 in 2000

hope this is what you were asking for!

step-by-step explanation:

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.