3x-y=11
2x+5y=-4

systems of linear equations using substitution
find x and y

The answer is x = 3, y = -2

The system of equations is:
3x - y = 11
2x + 5y = -4

Rewrite the first equation:
y = 3x - 11

Substitute y in the second equation and solve x:
2x + 5(3x - 11) = -4
2x + 5 * 3x + 5 * (-11) = -4
2x + 15x - 55 = -4
17x = 55 - 4
17x = 51
x = 51 / 17 
x = 3

Substitute x in the equation: y = 3x - 11
y = 3 * 3 -11
y = 9 - 11
y = -2

The answer is the numbers between =5 and 5