You randomly choose a tile. Without replacing the first tile, you choose a second tile. Find the probability of the compound event. Write your answer as a fraction or percent rounded to the nearest tenth. The probability of choosing two even numbers is

Complete question :

You randomly choose a tile. Without replacing the first tile, you choose a second tile. Find the probability of the compound event. Write your answer as a fraction or percent rounded to the nearest tenth. The probability of choosing two even numbers is

Tiles : 7,6, 5, 8, 9, 10, 20

2 /7

Step-by-step explanation:

The probability of a compound event in the scenario described above :

P(1st pick) * p(second pick)

Recall: this event is without replacement

P(choosing two even numbers)

Probability = required outcome / Total possible outcomes

Required outcome = even Number tiles = (6, 8, 10, 20) = 4

Total possible outcomes = number of tiles = 7

P(even number on first pick) = 4/7

P(even on second pick) = 3 / 6 = 1/2

P(compound event) = 4/7 * 1 /2 = 4 /14 = 2 /7

168

step-by-step explanation:

i am pretty sure that the answer is 168