What is the maximum or minimum value of f(x) = x² + 16x + 60

Minimum value is equal to x=8, y=-4
First find the derivative of the original equation which equals= d/dx(x^2-16x+60) = 2x - 16
at x=8, f'(x), the derivative of x equals zero, so therefore, at point x = 8, we have a minimum value.
Just plug in 8 to the original equation to find the answer for the minimum value.