Where would it go I know how to do X axis but not Y

(-1,2) and (2,2) Make sure to see explanation!

Step-by-step explanation:

Well you need to remember the Y reflection rule!

To reflect over the Y axis you must do this:

Take the points in this case

(1,2) and (-2,2)

And you need to use the equation (x,y) --> (-x,y)

So the new points you NEED TO GRAPH ARE

(-1,2) and (2,2)

Hope this helped!

(-1,2) and (2,2)

Step-by-step explanation:

reflection over the y axis, take the point (x,y) and change the sign of the X-value (-x,y). When You reflect over the y-axis, the y remains the same.

point (1,2) would become (-1,2) reflected over the Y

and (-2,2) would become (2,2)

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).