Can some one plz help me

Step-by-step explanation:

A is midpoint of DB

DA ≅ AB  (I)

B is midpoint of AE

BE≅ AB (II)

From (I) & (II)

DA ≅ AB    

∠D ≅ ∠E                Given

CD ≅  CE               {Sides opposite to equal angles are equal}

ΔCDA ≅ ΔCEB     { S A S congruent}

AB = BA                            reflexive property

AB = BE and DA = AB     definition of midpoint

then DA = EB                            

CD = CE                           ΔCDE is isosceles

ΔCDA ≅ ΔCEB                SAS

Step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10