If nkf ~ lzf, find nf, please help me with this it’s due tmr

NF = 25

Step-by-step explanation:

Since ∆NKF ~ ∆LZF, the ratio of their corresponding side lengths would also be the same.

This means that:

KF/ZF = NF/LF

KF = x + 3

ZF = 4

NF = 15 + x + 3 = x + 18

LF = x + 3

Plug in the values into the equation

(x + 3)/4 = (x + 18)/(x + 3)

Cross multiply

(x + 3)(x + 3) = (x + 18)(4)

x² + 3x + 3x + 9 = 4x + 72

x² + 6x + 9 = 4x + 72

x² + 6x + 9 - 4x - 72 = 0

x² + 2x - 63 = 0

Factorize to find x

x² + 9x - 7x - 63 = 0

x(x + 9) -7(x + 9) = 0

(x + 9)(x - 7) = 0

x + 9 = 0 or x - 7 = 0

x = -9 or x = 7

We'd use the positive value of x, which is 7.

Therefore, x = 7.

✅NF = 15 + (x + 3)

Plug in the value of x

NF = 15 + (7 + 3) = 15 + 10

NF = 25

what? that isnt a question

step-by-step explanation: