The box and whisker plot represents the number of telemarketing calls received by households last month. Which statements are correct?

A)

The mean of the data is 49.

B)

The median of the data is 49.

The least number of calls is 35.

D)

The third quartile is represented by 42.

E)

The mean cannot be determined by the box and whisker plot.

Given:

Consider the below figure attached with this question.

To find:

The correct statements about the given box and whisker plot.

Solution:

In a box plot, the left end of the box is first quartile and the right end of the box is third quartile. The line inside the box represents the median.

Left end point represents the minimum value and the right end point represents the maximum value.

From the given box plot, it is clear that

Minimum value = 35

First quartile = 42

Median = 49

Third quartile = 54

Maximum value = 57

The median of the data is 49. The least number of calls is 35. So, options B and C are correct.

The third quartile is represented by 54. So, option D is incorrect.

The mean cannot be determined by the box and whisker plot. So, option E is correct and option A is incorrect.

Therefore, the correct options are B, C and E.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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