The number of miles that regular tires last has a Normal distribution with a mean of 50,000 miles and a standard deviation of 8,200 miles. A competitor creates a new brand of tire, SuperWear Tires. The number of miles that SuperWear lasts has a Normal distribution with a mean of 75,000 miles and a standard deviation of 15,500 miles. If a random sample of 16 regular tires is selected and a random sample of 25 SuperWear tires is selected, the probability that the sample mean number of miles of SuperWear is greater than the sample mean number of miles obtained by the regular tires is approximately 1

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$27.5

step-by-step explanation:

$110.00 divided by 4

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).