Prob(Total time in process > Td) = EXP(-Td/T) T = (1/(Rp - Ri)) = (1 / Rs) R = min(Ri, Rp) u=R/Rp Dominic runs an appliance repair shop and sells replacement parts for appliances to walk in customers. Customers take an average of 5 minutes. It is a single phase system with 1 server. The coefficient of arrivals and the coefficient of processing times is 1.0. If the total time a customer is in the system is 10 minutes, what is the probability that a customer will have more than 15 minutes in the system?

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times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

a

step-by-step explanation:

the answer is a

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5