Data from a representative sample were used to estimate that 31% of all computer users in a recent year had tried to get on a Wi-Fi network that was not their own in order to save money. You decide to conduct a survey to estimate this proportion for the current year. What is the required sample size if you want to estimate this proportion with a margin of error of 0.05

The required sample size is 329.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error is:

31% of all computer users in a recent year had tried to get on a Wi-Fi network that was not their own in order to save money.

This means that

Confidence level is not given, so we assume 95%.

95% confidence level

So , z is the value of Z that has a pvalue of , so .

What is the required sample size if you want to estimate this proportion with a margin of error of 0.05?

We need a sample size of n. n is found when M = 0.05. So

Rounding up

The required sample size is 329.

i think there was a typo. you wrote pat brings 3 quarts of ice-cream to the party. each serving of ice-cream is 1 6 quart. how many total servings of ice-cream does pat bring to the party? i think the bold is supposed to be 1/6. so 1 quart of ice cream = 6 servings. 6 * 3 = 18.

step-by-step explanation: