Find the equation of straight line passing through the point: a) (4,8) and parallel to the line 3x+y=17
b) (2,3) and perpendicular to the line y=2x+13
I need the answers ASAP please!

See solution below

Step-by-step explanation:

Standard equation of a line in point slope form is expressed as y-y0 = m(x-x0)

m is the slope

c is the intercept

Fr the equation 3x+y = 17

y = -3x+17

m = -3

Given the point (4,8)

The equation of the line is expressed as;

y - 8 = -3(x-4)

y - 8 = -3x + 12

y + 3x = 12+8

y+3x = 20

This gives the required equation

For the equation y = 2x + 13

Slope m = 2

Since the line is perpendicular to the unknown line;

M = -1/2

Given the point (2, 3)

Get the equation

y - 3 = -1/2(x - 2)

2(y-3) = -(x - 2)

2y-6 = -x+2

2y+x = 2 + 6

2y+x = 8

This gives the required equation

there are no short passages to look at

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are