A certain field is a rectangle with a perimeter of 818 feet. The length is 175 feet more than the width. Find the width and length of the rectangular field.

9514 1404 393

Step-by-step explanation:

Let w represent the width of the field. Then w+175 is its length. The perimeter is ...

  P = 2(L+W)

  818 = 2((w+175) +w) . . . . . fill in given values

  818 = 4w +350 . . . . . . . . . simplify

  468 = 4w . . . . . . . . . subtract 350

  117 = w . . . . . . . . divide by 4

  w+175 = 292 . . . . find the corresponding length

The width of the field is 117 feet; the length is 292 feet.

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