Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42m​-by-42m square. Val says the area is 1005.48 m^2. Find the area enclosed by the figure. Use 3.14 for pi. What error might Val have​ made? Thanks in advance!
I don't have anymore points so please make a good and accurate answer.

Area of the enclosed figure = 3148.74

Step-by-step explanation:

Area enclosed by the figure = 2 x area of the semicircle + area of the square

For the semicircle,

radius =

          =

          = 21 m

area of a semicircle = x

                                = x 3.14 x

                                = 692.37

area of a square = length x length

                            = 42 x 42

                            = 1764

Thus,

area enclosed by the figure = 2 x 692.37 + 1764

                                              = 3148.74

The total area enclosed bu the figure is 3148.74

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100