Please help with this math question'

The rocket's maximum height will be 1424 feet.

It will reach that height in 4 seconds.

It will reach the ground  in 8 seconds.

Step-by-step explanation:

One easy way to find the peak is to find the derivative and solve for zero:

h(t) = -16t² + 128t + 1680

To find the derivative of each term in that format, you simply multiply the coefficient by the exponent, and reduce the exponent by one.  In the case of terms with no variable, they disappear.  That gives us:

h'(t) = -32t + 128

This derivative describes the rate of change of h with respect to t, so to find the peak, we simply need to solve it for zero:

0 = -32t + 128

32t = 128

t = 4

So the maximum height occurs when t = 4.  Let's plug it in to the original equation:

h(t) = -16t² + 128t + 1680

h(4) = -256 + 512 + 1680

h(4) = 1424

So the rocket's maxiumum height is 1424 feet.

And we've already answered the second question, it happens at 4 seconds.

Also, the amount of time going up will be the same as the amount of time going down, which means that it will reach the ground in twice that time, or 8 seconds.

-3.5 degrees per hour

step-by-step explanation:

find the unit rate:

-12   1/4 degrees           12.25 degrees

= - = -3.5 degrees per hour

      3   1/2 hours               3.5 hours

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6