What is the standard deviation of a normal distribution who meet us 35 in which an X value of 23 has a Z score of -1.63

7.362

Step-by-step explanation:

Given :

Mean = 35

Score, x value = 23

Zscore = - 1.63

Recall the Zscore formula :

Zscore = (X - mean) / standard deviation

-1.63 = (23 - 35) / standard deviation

-1.63 = - 12 / standard deviation

standard deviation * - 1.63 = - 12

Divide both sides by - 1.63

Standard deviation = - 12 / - 1.63

Standard deviation = 7.362

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

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