A game has 28 white balls and 12 red balls in a bag, and you will randomly select one ball from the bag. If the selected ball is white, you lose $5. And, if the ball is red, you win $10. What is the expected value of
the game?

There are 40 balls in the bag. The probability of selecting a white ball is 28/40, simplified to 7/10. The probability of selecting a red ball is 12/40, simplified to 3/10. You are more likely to get a white ball so you will most likely lose $5.

Step-by-step explanation:

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step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15