Do not factor by grouping. Solve 2(x-2)^1/3=x+2

Step-by-step explanation:

2(x-2)⅓=x+2

so we first cube each side,such that...

(2(x-2))⅓•³=(x+2)³

we get...

2(x-2)=(x+2)³

expanding...

2x-4=x³+6x²+12x+8

grouping

x³+6x²+12x+8-2x+4=0

solving...

x³+6x²+10x+12=0

now you can use you calculator to solve for the possible values of x

I hope this will help

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1