Find four solutions of each equation. Write the solutions as ordered pairs. 3. y = 3x
4. y = -2x + 11

y = 3x

x y

-2 -6

-1 -3

0 0

1 3

y = -2x +11

x. y

-1. 13

0 11

1. 9

2. 7

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e