The ends of a triangular prism are right triangles with a base of 12 inches and height of 9 inches. The height of the prism is 11 inches what is the surface area?

Given:

The bases of triangular prism are right triangles with a base of 12 inches and height of 9 inches.

The height of the prism is 11 inches.

To find:

The surface area of the triangular prism.

Solution:

Using the Pythagoras theorem, the hypotenuse of the bases of the triangular prism is:

Taking square root on both sides.

The surface after of the triangular prism contains 3 rectangles of dimensions 12 inches by 11 inches, 9 inches by 11 inches, 15 inches by 11 inches and two triangles with base 12 inches and height 9 inches.

Area of the rectangle:

So, the area of three rectangles are:

Area of a triangle is:

So, the area of the triangles is:

And, the triangles have same dimensions so their areas are equal.

Now,

Therefore, the surface area of the triangular prism is 504 sq. inches.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

i think 5 miles per hour

step-by-step explanation: