If P = (-2,-1) and Q = (4,3) are the endpoints of the diameter of a circle,
find the equation of the circle.
(x - [?])2 + (y - [ ])2 = []

Step-by-step explanation:

P(-2,-1) and Q(4,3)

average of x-coordinates = (-2+4)/2 = 1

average of y-coordinates = (-1+3)/2 = 1

midpoint of PQ: (1,1)

distance between midpoint and Q = √((4-1)²+(3-1)²) = √13

(x-1)² + (y-1)² = 13

w'x is 0.

hope it