Write x2 + 12x + 6 = 0 in vertex form using the completing-the-square method. (2 points) a
(x - 12)2 - 30 = 0

b
(x - 6)2 + 36 = 0

c
(x + 6)2 - 30 = 0

d
(x + 12)2 + 36 = 0

If sin(x) = 0 and cos(x) = 1, what is tan(x)?

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.

In a young single person's monthly budget, $150 is spent on food, $175 is spent on housing, and $175 is spend on other items. suppose you drew a circle graph to represent this information, what percent of the graph represents housing?