Suppose y varies jointly as x and z. If y=15 when x=1/2 and z=6, what is the constant of variation?

k = 5

Step-by-step explanation:

Given y varies jointly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = 15 when x = and z = 6 , then

15 = k × × 6 = 3k ( divide both sides by 3 )

5 = k

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.

step-by-step explanation:

which statement is true about the local minimum of the graphed function?

over the interval [–4, –2], the local minimum is 0.

over the interval [–2, –1], the local minimum is 25.

over the interval [–1, 4], the local minimum is 0.

over the interval [4, 7], the local minimum is -7.