Triangle PQR has the following coordinates: P (-9,-12) Q(-6, -13) R(-7, -4)

Where is Q' after a rotation 90° clockwise?

Please write your answer as a coordinate: (x, y)

The coordinates of Q’ are (-13,6)

Step-by-step explanation:

Here, we want to get the coordinates of the point Q’ obtained by rotating point Q at a degree of 90 clockwisely

Generally, we have the formula for the rotation as follows;

(x,y) will then (y,-x)

Thus,

(-6,-13) will become (-13, -(-6)) = (-13,6)

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!