9. A bag of M&M's contains 4 red, 1 blue, 3 yellow, and 2 brown. What is the probability of Maggie choosing a yellow M&M, eating it, and then choosing another yellow M&M?

1/15

Step-by-step explanation:

Given that:

Total Number of M&M's = (4 + 1 + 3 + 2) = 10

Number of yellow M&M's = 3

Probability = required outcome / Total possible outcomes

First pick (choosing without replacement)

P(choosing a yellow M&M) = 3 / 10

Second pick :

P(choosing a yellow M&M) = 2 / 9

P(choosing 2 yellow M&M) = 3/10 * 2/9 = 6/90 = 1/15

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