Please help me, this question is a bit tricky for me! The water of a tank is initially 24 feet, and it is being drained at a rate of 3 feet per day. The
equation below expresses the water level, y, in feet, in terms of the number of days, x, since
the tank began draining.

y = 24 − 3x

A scientist might be interested in the x-intercept of this equation because it represents the
moment when the tank will be empty. Which of the following is the x-intercept of the
equation above?

No cheating: you’re starring in a movie w/ the last person saved in your camera roll and the last song you listened to is the title.

"let's go everywhere" the movie with taemin and taeyong sounds like something i would watch ♡ https://t.co/tGdUt7CKPcNo cheating: you’re starring in a movie w/ the last person saved in your camera roll and the last song you listened to is the title.

"let's go everywhere" the movie with taemin and taeyong sounds like something i would watch ♡ https://t.co/tGdUt7CKPc

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: