There are two consecutive positive even integers such that the square of the first is 364 more than five times the second. What are the two numbers?

Step-by-step explanation:

There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?

Two consecutive year positive integers are represented by

x and x + 1

First integer = x

Second integer = y

There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.

This is represented mathematically as:

x² = 364 + 5(x + 1)

x² = 364 + 5x + 5

x² -5x -5 - 364

x² - 5x - 369

i think is g(1)=-1.

hope that i can

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!