According to Newton's Law of Cooling, T =S +(T. -Se kl whereby T = the final temperature after t time has passed
S = the surrounding (ambient) temperature
To = the initial temperature of the object
k= a constant (depends on the material)
t = the time that has passed.
Initially, my coffee is 210°F. After 2 minutes, it's 180°F. How long, to the nearest tenth of a minute, would it
take for the coffee to drop to a temperature of 130°F in a room where the temperature is set to 70°F?
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