Which shows how to use similar right triangles to find the equation of the line through (0,5) and any point, (2, y), on the line?
m+bb
1-0, so y = mx + 6.
(x, y)
y-b
(1 mb)
1, so y - b = mx +b.
m2
(0, b)
X
(0,0)
1-0 = "=0, so y = mu.
m+b-b
-0 so x = my + mb.

show us the graphs dude

step-by-step explanation:

i think is g(1)=-1.

hope that i can

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph