Solve the system of equations. y=2x-4 and 3y=2x

Plug in for y the first equation, to get 3(2x-4)=2x, 6x-12=2x, subtract 2x from both sides and get 4x-12=0, add 12 to both sides to get 4x=12, divide both sides by 4 to get x=3 and plug that into the first equation to get y=2(3)-4, y=6-4=2 so x=3 and y=2

Step-by-step explanation:

a

step-by-step explanation:

given the 2 equations

- x + y = - 2 → (1)

2x - 3y = 4 → (2)

multiplying (1) by 2 and adding to (2) will eliminate the x- term

- 2x + 2y = - 4 → (3)

add (2) and (3) term by term

(2x - 2x) + (- 3y + 2y) = (4 - 4), simplifying gives

- y = 0 ⇒ y = 0

substitute y = 0 in either of the 2 equations for corresponding value of x

substituting in (2) gives

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 0 ) → a