Solve if possible. if not, indicate what information is needed. The width of a rectangle is 6 inches less than its length. the area of ​​the rectangle is 135 inches squared. find the length and width.​

W = Width

L = Length

A = Area

W = L - 6

A = W * L

135 =( L - 6 ) * L

135 = L ^ 2 - 6 L

The exact solution are :

L = - 9 cm

and

L = 15 cm

The length can't be negative so:

L = 15 cm

W = L - 6

W = 15 - 6 = 9 cm

A = W * L = 15 * 9 = 135 cm ^ 2

P. S.

If you don't know how to solve equation:

135 = L ^ 2 - 6 L

hope this helps u

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

(23*2)-12=x     x=34

step-by-step explanation: