Find the nth terms of the following Ap 100, 91, 82​

The nth term is 109-9n

Step-by-step explanation:

Here, we want to find the nth term of the given arithmetic sequence

Mathematically, we have the nth term as;

Tn = a + (n-1)d

where a is the first term which is 100 in this case

d is the common difference which is the value obtained by subtracting the preceding term from the succeeding term; it is constant throughout the sequence

The value here is thus;

82-91 = 91-100 = -9

Substituting these values

Tn = 100 + (n-1)-9

Tn = 100 -9n + 9

Tn = 100 + 9 - 9n

Tn = 109-9n

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.