A jar contains 3 orange balls, 3 yellow balls, and 4 red balls. Providing the ball drawn first is replaced before the second is drawn. What is the probability of selecting: 1. 2 orange balls
2. 2 yellow balls
3. 1 red and 1 yellow ball

Given:

Number of orange balls = 3

Number of yellow balls = 3

Number of red balls = 4

To find:

The probability of:

1) 2 orange balls

2) 2 yellow balls

3) 1 red and 1 yellow ball

Solution:

We know that,

The total number of balls is

Using the above formula, we get

The ball drawn first is replaced before the second is drawn. So, the probabilities remains unchanged.

1) The probability of getting the 2 orange balls is

Therefore the probability of getting the 2 orange balls is 0.09.

2) The probability of getting the 2 yellow balls is

Therefore the probability of getting the 2 yellow balls is 0.09.

3) The probability of getting the 1 red and 1 yellow ball is

Therefore the probability of getting the 1 red and 1 yellow ball is 0.12.

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (

17.08

correct me if i am wrong.