Find the indicated side length round to the nearest tenth),

Step-by-step explanation:

for 1 they give us an angle and the side next to that angle.. or the Adjacent side and they want to know the Opposite side from the angle sooo let's use ..

SOH CAH TOA    

hmm TOA seems good , it's got the adj and Opp in it ,

Tan(Ф) = Opp / Adj

Tan(67) = Opp / 26

26 * Tan(67) = Opp

61.2521 = Opp

61.3  ( rounded to nearest 10th )    does this seem big to you?  well it should be quite a bit bigger than the 25 on the base, seems about right to me

for 2 they give us one angle, 48 , and one side, 35 , that is opposite from that angle,  and ask what is the Hyp.  So find a trig function that has those pieces in it.     SOH seems good

sin(Ф) = Opp / Hyp

sin(48) = 35 / Hyp

Hyp = 35 / sin(48)

Hyp = 47.0971  ( and that seems about right for the Hypotenuse )

x = 47.1  ( rounded to the nearest 10th )

for 3  they are asking us to imagine a triangle, I'll draw it and attach it as a picture.    Looking at the picture helps a lot, we can see we have the angle and the adj side and want to find the Opposite side of that big triangle. sooo   use TOA  , it's got those pieces in it

Tan(17) = Opp / 200

200*Tan(17) = Opp

61.1461  =Opp

so the height of the radio mast is  61.1 meters  ( rounded to nearest 10th )

Does this seem a bit easier when you think about how the parts of the trig functions fit on the triangles?    :)   ask if you have any questions

the answer is b

your answer is the frist one

hop i