The total number of victories for a football team exceeds the number of defeats by 4, with no draws. Knowing that if 44 jojos, how many victories were there?

24

Step-by-step explanation:

Let the number of defeats be represented by x.

Since the total number of victories exceeds the number of defeats by 4, then the number of victories will be:

= x + 4

We then add the number of victories and losses together and equate them to 44. This will be:

x + x + 4 = 44

2x + 4 = 44

2x = 44 - 4

2x = 40

x = 40/2

x = 20

Therefore number of victories will be:

= x + 4

= 20 + 4

= 24

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )