PLS HELP.
Amy and Richard each solved an equation using the quadratic formula.
Amy's Equation...
Mathematics, 24.03.2021 22:00 xmhllo
PLS HELP.
Amy and Richard each solved an equation using the quadratic formula.
Amy's Equation and Method
Latex: 4x^2+7x-20=0
4
x
2
+
7
x
β
20
=
0
4
x
2
+
7
x
β
20
=
0
Step 1: Latex: x=\frac{-7\pm \sqrt{7^2-4(1)(20)}}{2(4)}
x
=
β
7
Β±
β
7
2
β
4
(
1
)
(
20
)
2
(
4
)
x
=
β
7
Β±
7
2
β
4
(
1
)
(
20
)
2
(
4
)
Step 2: Latex: x=\frac{-7\pm \sqrt{49-80}}{8}
x
=
β
7
Β±
β
49
β
80
8
x
=
β
7
Β±
49
β
80
8
Step 3: Latex: x=\frac{-7\pm \sqrt{-31}}{8}
x
=
β
7
Β±
β
β
31
8
x
=
β
7
Β±
β
31
8
Step 4: Latex: x=\frac{-7\pm i\sqrt{31}}{8}
x
=
β
7
Β±
i
β
31
8
x
=
β
7
Β±
i
31
8
Richard's Equation and Method
Latex: x^2-6x+8=0
x
2
β
6
x
+
8
=
0
x
2
β
6
x
+
8
=
0
Step 1: Latex: x=\frac{6\pm \sqrt{(-6)^2-4(1)(8)}}{2(1)}
x
=
6
Β±
β
(
β
6
)
2
β
4
(
1
)
(
8
)
2
(
1
)
x
=
6
Β±
(
β
6
)
2
β
4
(
1
)
(
8
)
2
(
1
)
Step 2: Latex: x=\frac{6\pm \sqrt{36-32}}{2}
x
=
6
Β±
β
36
β
32
2
x
=
6
Β±
36
β
32
2
Step 3: Latex: x=\frac{6\pm \sqrt{4}}{2}
x
=
6
Β±
β
4
2
x
=
6
Β±
4
2
Step 4: Latex: x=\frac{6+\sqrt{4}}{2}
x
=
6
+
β
4
2
x
=
6
+
4
2
and Latex: x=\frac{6-\sqrt{4}}{2}
x
=
6
β
β
4
2
x
=
6
β
4
2
Step 5: Latex: x=\frac{6+2}{2}
x
=
6
+
2
2
x
=
6
+
2
2
and Latex: x=\frac{6-2i}{2}
x
=
6
β
2
i
2
x
=
6
β
2
i
2
Step 6: Latex: x=4
x
=
4
x
=
4
and Latex: x=3-i
x
=
3
β
i
x
=
3
β
i
Both students made a mistake.
Describe the mistake each student made.
Explain what each student needs to do to fix their mistake.
Create your own quadratic equation, and explain how to use the quadratic formula to solve it. Be specific, using Latex: a\textsf{, }b\textsf{,} and Latex: c
c
c
of your equation and giving the solutions to the equation you chose.
Number your responses from 1 to 3 so your instructor can tell which question you're responding to. You may not receive full credit if your teacher cannot determine that you've answered each question.
Answers: 1
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